WEBVTT 00:00:00.000 --> 00:00:03.410 The Gram Stain is the most widely employed staining method 00:00:03.410 --> 00:00:05.276 in microbiology. 00:00:05.276 --> 00:00:10.009 It is a differential stain because it divides bacteria into 2 classes: 00:00:10.009 --> 00:00:13.193 gram positive and gram negative. 00:00:13.193 --> 00:00:16.276 In the first step of the gram stain procedure, 00:00:16.276 --> 00:00:20.093 cells from a fresh culture are transferred to a clean slide 00:00:20.093 --> 00:00:21.809 and allowed to dry. 00:00:21.809 --> 00:00:25.626 If the cells are on an augur plate, they should first be transferred 00:00:25.626 --> 00:00:28.476 to a liquid medium for dilution. 00:00:28.476 --> 00:00:32.426 The cells should form a thin, barely visible film. 00:00:32.426 --> 00:00:34.525 This can be achieved by smearing cells 00:00:34.525 --> 00:00:37.226 obtained from the surface of an augur medium 00:00:37.226 --> 00:00:39.559 or from a liquid culture. 00:00:39.559 --> 00:00:43.308 Fresh cultures must be used because as cells age, 00:00:43.308 --> 00:00:46.359 they lose their ability to retain the stain. 00:00:46.359 --> 00:00:50.109 The cells are then fixed to the slide by passing slightly 00:00:50.109 --> 00:00:52.776 above the flame of a Bunsen burner. 00:00:52.776 --> 00:00:56.159 After passing above the flame, the slide should feel warm 00:00:56.159 --> 00:01:00.142 when touched to the back of the hand; but should not be too hot. 00:01:00.142 --> 00:01:04.825 The fixed cells are then stained with the basic dye, crystal violet, 00:01:04.825 --> 00:01:07.158 for 30 to 40 seconds. 00:01:07.158 --> 00:01:11.243 The slide is then rinsed with water to remove excess stain. 00:01:11.243 --> 00:01:15.258 At this point, all cells appear purple under the microscope. 00:01:15.258 --> 00:01:19.742 Next, a solution of Grams iodine is added and retained on the slide 00:01:19.742 --> 00:01:21.675 for about 1 minute. 00:01:21.675 --> 00:01:24.359 The iodine combines with the crystal violet 00:01:24.359 --> 00:01:29.108 to form a dye-iodine complex, thereby decreasing its solubility 00:01:29.108 --> 00:01:30.541 within the cell. 00:01:30.541 --> 00:01:34.240 At this point, the cells still appear purple. 00:01:34.240 --> 00:01:39.240 The cells are then de-colorized by washing with ethanol or acetone. 00:01:39.240 --> 00:01:41.805 This is the differential step. 00:01:41.805 --> 00:01:45.424 Gram positive bacteria retain the crystal violet, 00:01:45.424 --> 00:01:48.873 whereas gram negative bacteria do not. 00:01:48.873 --> 00:01:52.524 The ethanol or acetone should be added dropwise 00:01:52.524 --> 00:01:56.306 with the slide tilted at an angle until the drop coming off 00:01:56.306 --> 00:01:59.923 the edge of the slide just starts to become colorless. 00:01:59.923 --> 00:02:05.005 Even gram positive cells can lose the crystal violet iodine complex 00:02:05.005 --> 00:02:08.659 during prolonged excessive de-coloration. 00:02:08.659 --> 00:02:12.259 Excess ethanol is then washed off with water. 00:02:12.259 --> 00:02:16.541 When viewed under the microscope, gram positive cells appear purple 00:02:16.541 --> 00:02:19.925 and gram negative cells are colorless. 00:02:19.925 --> 00:02:24.308 Finally, the rinsed cells are covered with the counter stain safranin 00:02:24.308 --> 00:02:26.542 for 20 to 30 seconds. 00:02:26.542 --> 00:02:29.825 This stains the gram negative bacteria pink. 00:02:29.825 --> 00:02:34.492 After rinsing with water, the slide is dried with filter paper. 00:02:34.492 --> 00:02:38.841 When viewed microscopically, the gram positive bacteria are purple 00:02:38.841 --> 00:02:41.908 and the gram negative bacteria are pink. 00:02:41.908 --> 00:02:46.224 Generally, the gram stain correlates with the cell wall structure 00:02:46.224 --> 00:02:47.924 among the bacteria. 00:02:47.924 --> 00:02:51.673 The ethanol is thought to shrink the thick peptidoglycan 00:02:51.673 --> 00:02:55.773 in gram positive cells, thus retaining the dye. 00:02:55.773 --> 00:02:58.647 The thick dehydrated peptidoglycan layer 00:02:58.647 --> 00:03:03.180 of gram positive bacteria appears to be a permeability barrier 00:03:03.180 --> 00:03:07.163 preventing the loss of the crystal violet iodine complex. 00:03:07.163 --> 00:03:12.579 In contrast, the peptidoglycan in gram negative bacteria is very thin, 00:03:12.579 --> 00:03:14.663 and has large pores. 00:03:14.663 --> 00:03:18.445 Ethanol may extract lipids and increase the porosity 00:03:18.445 --> 00:03:21.713 thus removing the crystal violet iodine complex.