1
00:00:00,760 --> 00:00:02,395
Burada Rieman cəmimiz var.

2
00:00:02,395 --> 00:00:04,925
Limiti n sonsuzluğa yaxınlaşırmış kimi
götürəcəyik

3
00:00:04,925 --> 00:00:06,157
və bu videoda

4
00:00:06,157 --> 00:00:08,137
bu ifadəni müəyyən inteqral şəklində

5
00:00:08,137 --> 00:00:09,756
yenidən yazmağı sınayacağıq.

6
00:00:09,756 --> 00:00:11,176
Videonu dayandırıb

7
00:00:11,176 --> 00:00:14,775
misalı özünüz həll etməyə
çalışa bilərsiniz.

8
00:00:14,775 --> 00:00:16,054
Gəlin

9
00:00:16,054 --> 00:00:20,428
Rieman cəminin müəyyən inteqralla
necə əlaqəli olduğunu xatırlayaq.

10
00:00:20,428 --> 00:00:24,345
Əgər
a-dan b-yə

11
00:00:27,287 --> 00:00:29,120
f(x) dx-in müəyyən inteqralı varsa,

12
00:00:34,052 --> 00:00:36,391
başqa videolardan da bildiyimiz kimi,

13
00:00:36,391 --> 00:00:38,900
o,

14
00:00:38,900 --> 00:00:43,067
n sonsuzluğa yaxınlaşdıqda

15
00:00:44,743 --> 00:00:47,076
i bərabərdir 1-dən n-ə cəmin limitinə
bərabər olacaq.

16
00:00:47,918 --> 00:00:49,566
Əslində,

17
00:00:49,566 --> 00:00:51,720
biz enini

18
00:00:51,720 --> 00:00:55,093
delta x şəklində yazacağımız düzbucaqlıların

19
00:00:55,093 --> 00:00:57,260
cəmini tapacağıq.

20
00:00:58,142 --> 00:01:00,916
Yəni enimiz

21
00:01:00,916 --> 00:01:02,777
delta x olacaq və

22
00:01:02,777 --> 00:01:03,736
hündürlüyümüz isə

23
00:01:03,736 --> 00:01:06,292
delta x-də hesablanan

24
00:01:06,292 --> 00:01:08,434
funksiyamızın qiyməti olacaq.

25
00:01:08,434 --> 00:01:10,128
Əgər düzgün Rieman cəmi ediriksə,

26
00:01:10,128 --> 00:01:12,799
---

27
00:01:12,799 --> 00:01:14,412
---

28
00:01:14,412 --> 00:01:18,580
Yəni biz aşağı sərhəd olaraq
a-dan başlayacağıq

29
00:01:18,580 --> 00:01:22,747
və indeksimizin müəyyən etdiyi qədər
delta x-ləri əlavə edəcəyik.

30
00:01:23,775 --> 00:01:25,198
Əgər i 1-ə bərabərdirsə,

31
00:01:25,198 --> 00:01:26,942
biz bir delta x əlavə edəcəyik,

32
00:01:26,942 --> 00:01:28,962
---

33
00:01:28,962 --> 00:01:31,356
Əgər i 2 olsaydı, biz 2 delta x əlavə edəcəkdik.

34
00:01:31,356 --> 00:01:34,630
Bu, delta x vur

35
00:01:34,630 --> 00:01:35,963
indeksə bərabər olacaq.

36
00:01:37,058 --> 00:01:38,623
Bu, daha əvvəl də gördüyümüz

37
00:01:38,623 --> 00:01:40,649
ümumi formadır.

38
00:01:40,649 --> 00:01:42,383
Burada nümunələri

39
00:01:42,383 --> 00:01:44,373
uyğunlaşdıra bilərik.

40
00:01:44,373 --> 00:01:47,406
Funksiyamız natural loqarifma 
kimi görünür?

41
00:01:47,406 --> 00:01:49,129
yəni bizim funksiyamız

42
00:01:49,129 --> 00:01:51,952
natural loqarifmadır.

43
00:01:51,952 --> 00:01:53,330
Deməli, biz

44
00:01:53,330 --> 00:01:56,830
f(x) bərabərdir lnx yaza bilərik.

45
00:01:58,463 --> 00:02:00,079
Başqa nə görürük?

46
00:02:00,079 --> 00:02:02,496
Belə görünür ki, a 2-yə bərabərdir.

47
00:02:03,583 --> 00:02:05,575
a 2-yə bərabərdir.

48
00:02:05,575 --> 00:02:08,110
Delta x nəyə bərabər olacaq?

49
00:02:08,110 --> 00:02:10,572
Buradan da görə bildiyimiz kimi,

50
00:02:10,572 --> 00:02:12,368
bu vuruğumuz

51
00:02:12,368 --> 00:02:14,572
hansı ki, n-ə bölünüb

52
00:02:14,572 --> 00:02:17,191
və i-ə vurulmayıb

53
00:02:17,191 --> 00:02:19,582
delta x-ə bənzəyir.

54
00:02:19,582 --> 00:02:22,798
Buradakı isə delta x vur i-dir.

55
00:02:22,798 --> 00:02:26,965


56
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57
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