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pumping test analysis part2

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    Speaker: Nay wells are affected by a well
    skin, a low permeability layer that
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    surrounds the well and causes the drawdown
    in the skin to be less than- er to be
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    greater than the drawdown that
    would be expected otherwise.
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    So, we can see this in the, in the sketch.
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    This line here is the expected drawdown
    using, uh, the Jacob analysis, or
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    perhaps some other analysis, but as we
    get right in the vicinity of the well, we
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    see that there's a low permeability zone
    here, and the head goes like so, follows
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    this dashed line.
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    And as a result, this is the expected
    drawdown based on our theoretical analysis.
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    It is using the properties of the aquifer,
    uh, out here away from the well
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    [stammering] in this region, but in fact
    we observe that the drawdown at the well
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    is here, so the drawdown is greater, um,
    and that results from the extra headloss
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    due to the well skin.
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    So we want to characterize this, and one
    way to characterize it is to use the well
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    efficiency, which is the ratio of the
    expected drawdown from our theoretical
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    analysis to the observed drawdown,
    what actually occurs in the field.
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    So we need a way to calculate what the
    expected drawdown is, and we can do
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    this with the Jacob analysis.
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    What I'm showing here is a version of the
    Jacob analysis that's set up to calculate
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    the head- er I guess this is the drawdown
    here, um, as a- at a particular time.
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    So, the important thing to recognize is
    right here.
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    The radial distance that we're using here
    is the radius of the well.
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    What we used in the previous analysis
    was the radial distance of the monitering
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    well, where our data were made.
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    In this case, we need to use the radial-
    the radius of the well itself.
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    This time here, that's the time, the
    elapsed time, for a data point that we're
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    gonna use to determine the observed
    drawdown.
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    The calculation goes like so: we put in
    the observed time and the radius
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    of the well, and everything else is pretty
    much the same, the s and the t we've
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    calculated using a monitoring well out
    here in the formation.
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    The performance here of the monitoring
    well, the head in the monitoring well, is
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    not effected by the skin, so when we
    calculate TNS from the monitoring well
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    data, we're getting something that's
    really just affected by the, um,
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    formation properties.
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    And there is the same T and this is
    Q, which we already know, so we can
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    go and calculate what this is, this gives
    us an expected drawdown, which we then
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    take the ratio of, that calculated value
    to the reserve drawdown at that time.
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    That gives us the well efficiency.
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    Note also that it's possible, under some
    circumstances, for the well efficiency
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    to be greater than one.
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    In many cases, and in the one that I'm
    showing here, there's a low
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    permeability region around the well, and
    that often occurs as a result of drilling
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    or perhaps bacterial fouling, uh, during
    operation of the well.
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    But if possible that the well has a, uh,
    higher permeability region around
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    it, um, for example, here's our screen,
    and if it, if the well has been
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    hydraulically fractured, for example, or
    if the well intersects a region at its
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    higher permeability than the formation,
    then, uh, the drawdown that's expected
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    might be greater than the observed
    drawdown.
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    So, if this is a more permeable region,
    then we might have something that
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    looks like this, then goes like that.
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    And so the gradient here is less than
    what's expected.
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    The specific capacity of a well is the
    pumping rate, Q, divided by
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    the drawdown.
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    So during a transient test, this is going
    to be constantly changing.
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    If we hold the pumping rate constant, the
    drawdown will be increasing, and so this
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    will be decreasing.
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    This ratio.
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    But, if we have a shallow well, and we
    pump it for a while, then the drawdown
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    tends to stabilize, and the well goes to
    steady state, in which case, the
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    specific capacity reaches a constant
    value.
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    And this is a very important value to
    know because for a reasonable
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    range of drawdowns, in many cases,
    this constant, or this, this uh, specific
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    capacity is constant.
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    So if we know what it is, then we can
    tell what the drawdown will be for
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    a specific pumping rate.
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    And this is really, probably the best way
    to characterize the performance of
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    a well, at least if you're interested in
    how much rate you could get, how much
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    water you could get to come out of
    this well.
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    For a specific, if you know the specific
    capacity, then you can tell what the
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    drawdown will be if you pump it at
    a certain rate.
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    So for example, if there is a certain
    amount of drawdown that you can't
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    exceed, that'll be the maximum drawdown
    that you could tolerate, then you can
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    determine what the pumping rate would
    be when you reach that, if you were to
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    hold that, um, that drawdown to be
    constant.
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    Okay, so, for shallow wells, the way that
    they go to steady state is by interacting
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    with the stream.
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    And the way that you analyze this is to
    take a well over here, let me back up a
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    second, so this is what we're thinking is
    going on, here's the well, over here this
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    red circle, and we're pumping out, and
    there's a stream over here, shown by
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    this blue band.
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    And when a well goes to steady state, it's
    interacting with that stream, and that
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    interaction is what allows it to go to
    steady state.
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    So to analyze this situation, the way that
    you do it is to use what's called an
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    image well.
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    So, if we have a well here, and if we use
    just the Jacob Analysis, and we're
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    pumping out of this well, and we assume
    in the Jacob Analysis that the aquifer
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    is infinite, so it's an infinite lateral
    extent, and there is no boundary.
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    But what we do then is we say, well
    I'm gonna put in another well.
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    This is just an artificial well.
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    It doesn't really exist, but I'm gonna
    put it in there because if I, if I take
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    that well and then I inject into it, and
    if I inject into it at a rate that's
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    equal to the pumping rate that I'm
    doing over here, then this injection
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    offsets the pumping over on the
    left side, and as a result, the zone,
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    the line that's halfway between these
    two has no drawdown.
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    And so it's, it's the head along that
    line is maintained at constant value.
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    Alright, and as a result, this, uh,
    analysis, it's only valid for this
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    region over here, it's not really valid
    over here because this pumping
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    well doesn't really exist.
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    So it's a way of taking a, a simple
    analysis for an infinite la-aquifer, and
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    turning it into an analysis that will
    allow us to evaluate the effects of
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    a constant head boundary that represents
    a string.
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    So that's what I'm showing here, that the,
    the drawdown will equal the actual
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    drawdown from the pumping well, plus
    the drawdown from this image well
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    that's over here.
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    Here's how you do it.
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    This is the Jacob Analysis that we've
    seen before.
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    What we're gonna need to do is to
    write this now, in terms of
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    X and Y coordinates.
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    So there's X, and there's Y, and the
    origin of coordinates is at the, uh,
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    pumping well.
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    So, in order to do that, to make the
    switch, what we have to do is go in
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    here, and recognize that when we
    first did Jacob, we wrote it in terms of
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    radial distance away from the pumping
    well, that's because it was exactly
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    symmetric, and what we can do then is
    recognize that R squared is equal to
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    X squared plus Y squared.
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    That's the Pythagorean theorem.
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    So we just do that substitution, and we
    get this version of the equation, so
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    that's Jacob Analysis right there, we see
    this guy here, that's the, that's the
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    substitution that we've done.
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    So this is just the pumping well, and we
    can repeat this for the image well, and
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    here's what it looks like.
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    This is the image well, and we're gonna be
    injecting instead of pumping out, so the
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    sign changes right there.
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    And the image well is, is here.
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    It's at X equals 2L.
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    So L is the distance the distance to
    the stream, and this distance here
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    is 2L.
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    So the way that we write this image well
    is to replace X here with X minus 2L.
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    That's right there.
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    That kind of slides this image well over
    here to the origin of coordinates.
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    Otherwise, this is just the same as the
    pumping well.
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    So the image well, with just two small
    changes, we can, we can determine what
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    the drawdown is over here at the
    image well.
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    And now what we do is add them together,
    so this is another superposition problem,
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    we saw earlier that we did the analysis or
    recovery by superimposing two
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    solutions from different times, here we're
    superimposing two solutions from
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    different locations.
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    This is the pumping well, and this is the
    image well that we just drew out here.
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    And what we see is that this term here can
    be factored out, and then we have log,
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    log of this stuff here, minus the log of
    this stuff there.
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    And so we can combine those logs using
    the rule of logs when we have log of A
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    minus log of B, that equals the log of
    A divided by B.
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    So we do that, we combine them and
    we get this.
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    Um, these terms, this stuff here, it's
    just gonna cancel, when we do this
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    division and we end up with the stuff
    that I'm showing here.
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    Okay, so that's the total drawdown, this
    would give us the drawdown throughout
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    this region here.
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    Alright, so let's go to the next page, and
    here's the thing that we just developed.
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    So, what we do is say, well, we're really
    just interested in, for this specific
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    capacity calculation, and what the
    drawdown is at the well.
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    What we have here is X and Y, so, the
    solution that we have here is really
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    valid over the whole aquifer, but if we
    just say that the particular point we're
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    interested in, we say that Y is equal to
    zero, so that would be right here.
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    Well, it'd be right here.
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    And X equals RW, so that's gonna be
    right at that point there.
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    Um, and if we also assume that two
    times L is much, much greater than
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    RW, so that's, I think makes sense, so
    2L is, um, is, is, 2 times the distance to
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    the stream, and that's got to be much,
    much greater than the radius of the well.
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    So that'll be okay, unless the well is
    right next to the stream.
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    This'll be fine.
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    And if we make those assumptions, then,
    um, we're saying that R squared is, that's
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    just equal to zero.
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    And if we make, uh, we, we, this guy
    here, this X is equal to RW.
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    That's RW.
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    And that allows us to simplify this down
    to, to this, so pretty straightforward.
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    And then the next step is to recognize if
    we take the log of this stuff, squared,
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    that the two can come down, two can come
    down there, and that'll cancel out with
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    that guy and give us two there.
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    Okay, so here's the result.
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    For the drawdown at that point on the
    well.
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    And then to get specific capacity, we just
    take the Q over here and this is one over
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    the specific capacity, so we do one over
    all of this stuff, and we get this
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    analysis here, or this formula in the
    yellow box.
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    So this gives us a way to calculate this
    specific capacity at steady state,
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    assuming that the aquifer is going to
    steady state by interacting with
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    this stream.
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    And it's really a pretty straightforward
    calculation, we've already calculated T,
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    and we determined L, that's the distance
    to the nearest stream, so we'll
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    presumably have a, a map of the sight,
    the radius of the well, we'll know that
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    from the well completion, and so we can
    do this analysis out, and see what this
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    steady state specific capacity is.
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    And so what we're expecting is to have
    something, let's see, let's take a look at
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    the units, well this guy down here, uh,
    is, it's a log, so it has no units, and so
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    this has units of, uh, transmissivity, has
    units of length squared per time, so
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    the specific capacity has units of length
    squared per time, that's the basic units,
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    but if we think about it, Q over Delta P,
    this is telling us the, the flow rate per
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    unit of drawdown.
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    So, it's really the flowrate here.
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    Length cubed per time, per unit of
    drawdown is the length.
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    So, we can give the specific capacity
    at, in units of length squared per time,
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    that's correct, but what you see is that
    in some cases, it's also-it's given as
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    length cubed per time, the volumetric
    flow rate per unit of drawdown.
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    So, specific capacity sometimes is given
    as like, gallons per minute per foot of
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    drawdown, um, so, even though you could
    go and, and reduce it down to this kind
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    of unit, uh, because it's a, a flow rate
    per unit of drawdown, it's given as a,
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    as units that, that support that concept.
Title:
pumping test analysis part2
Description:

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Video Language:
English
Duration:
15:36

English subtitles

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