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- [Voiceover] So in the previous video
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we solved this problem the hard way.
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Maybe you watched it, maybe you didn't,
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maybe you just skipped right
to here and you're like,
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"I don't even wanna know the hard way.
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"Just show me the easy way please."
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Well, that's what we're
gonna talk about now.
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Turns out there's a trick
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and the trick is after you
solve this problem the hard way
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with a five kilogram mass
and a three kilogram mass,
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when you find the acceleration,
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what you get is this.
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That the acceleration of
the five kilogram mass
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is just 29.4 divided by eight kilograms.
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But when you do enough of these,
you might start realizing,
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"Wait a minute. 29.4 Newtons.
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"That was just the force of gravity
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"pulling on this three kilogram mass."
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In other words,
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the only force that was really propelling
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this whole entire system forward.
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Or at least the only external
force propelling it forward.
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And then eight kilograms down here.
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You're gonna be like,
"Wait. Eight kilograms?
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"That's just five kilograms
plus three kilograms.
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"Is that just a coincidence
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"or is this telling us
something deep and fundamental?"
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And it's not a coincidence.
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Turns out you'll always get this.
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That what you'll end up with
after solving this hard way,
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you'll get in the very end,
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you'll get all the external
forces added up here
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where forces that make it go
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like this force of gravity
end up being positive
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and forces that try to resist the motion.
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So if there was friction, that
would be an external force
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that tries to resist
motion, would be up top
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and then you get the
total mass on the bottom.
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And this makes sense.
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The acceleration of this entire system,
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if we think about it as a single object---
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So if you imagine this
was just one single object
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and you asked yourself,
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"What's the total acceleration
of this entire system?"
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Well, it's only gonna depend
on the external forces
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and in this case, the only
external force making it go
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was this force of gravity right here.
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You might object.
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You might be like, "Wait.
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"What about this tension right here?
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"Isn't the tension pulling
on this five kilogram mass
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"making this system go?"
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It is but since it's
an internal force now,
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if we're treating this entire
system as our one object,
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since this tension is
trying to make it go,
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you've got another tension over here
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resisting the motion on this mass,
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trying to make it stop.
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That's what internal forces do.
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There's always equal and opposite
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on one part of the object than the other
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so you can't propel yourself forward
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with an internal force.
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So these end up cancelling
out essentially.
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The only force you have in this case
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was the force of gravity on top,
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only external forces,
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and the total mass on the bottom.
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And that's trick.
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That's the trick to quickly find
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the acceleration of some system
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that might be complicated
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if you had to do it in multiple equations
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and multiple unknowns
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but much, much easier
once you realize this.
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So the trick, sometimes it's called
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just "Treating systems
as a single object".
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Let me just show you really quick.
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If that made no sense, let me
just show you what this means.
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If we just get rid of this.
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So what I'm claiming is this.
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If you ever have a system
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where multiple objects
are required to move
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with the exact same magnitude
of acceleration, right?
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Because maybe they're
tied together by rope
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or maybe they're pushing on each other.
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Maybe there's many boxes in a row
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and these boxes all have to be pushed
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at the same acceleration
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because they can't get
pushed through each other.
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Right, if there's some
condition where multiple objects
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must have the same
magnitude of acceleration,
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then you can simply find the
acceleration of that system
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as if it were a single object.
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I'm writing, "SYS" for system.
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By just using Newton's second law,
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but instead of looking
at an individual object
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for a given direction,
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we're just gonna do all
of the external forces,
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all of the external forces on our system,
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treat it as if it were a single object,
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divide it by the total mass of our system.
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And so when you plug in
these external forces---
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These are forces that are external
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so external means not
internal to the system.
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So if I think of this five kilogram box
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and this three kilogram
box as a single mass,
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tension would be an internal force
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because it's applied internally
between these two objects,
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between objects inside of our system.
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But the force of gravity
on the three kilogram mass,
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that's an external force
'cause that's the Earth
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pulling down on the three kilogram mass
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and the Earth is not part of our system.
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Similarly, the normal
force is an external force
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but it's exactly cancelled
by the gravitational force.
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So even though those are external,
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they're not gonna make it in here.
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I mean, you can put 'em in there
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but they're just gonna cancel anyway.
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We only look at forces in
the direction of motion
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and if it's a force that causes motion,
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we're gonna make that a positive force.
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If it's a force in the direction of motion
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like this force of gravity is,
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we make those positive forces.
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So forces will be plugged
in positive into here
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if they make the system go.
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And that might seem weird.
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You might be like, "Wait.
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"How do I decide if it
makes the system go?"
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Well, just ask yourself,
"Is that force directed
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"in the same direction as
the motion of the system?"
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So, we're just saying the
system is gonna accelerate
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if there's forces that make it go
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and we're gonna plug in negative forces,
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the forces that make the system stop
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or resist the motion of system.
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So maybe I should say,
"Resist motion of the system."
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In this case, for this one down here,
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I don't have any of those.
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So resist motion of the system.
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I don't have any of those.
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I could have if I had a force of friction.
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Then there'd be a external
force that resist the motion.
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I would plug in that
external force as a negative
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'cause it resist the motion.
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So even though this might sound weird,
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it makes sense if you think about it.
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The acceleration of our system
treated as a single object
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is only gonna depend on the forces
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that try to make the system go
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and the forces that try
to make the system stop
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or resist the motion.
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So if we add those accordingly
with positives and negatives,
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we divide it by the total mass
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which gives the total measure
of the inertia of our system,
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we'll get the acceleration of our system.
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It makes sense and it works.
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Turns out it always works
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and it saves a ridiculous amount of time.
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For instance, if we
wanted to do this problem,
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if you just gave me this
problem straight away
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and you were told, "Do
this however you want.",
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I would use this trick.
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And I would say that the
acceleration of this system
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which is composed of
this five kilogram mass
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and our three kilogram mass
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is just gonna be equal to---
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I'd ask myself, "What
force makes this system go?
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"What force drives this system?"
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And it's this force of gravity
on the three kilogram mass
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that's driving this system, right?
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If you took this force away,
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if you eliminated that force,
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nothing's gonna happen here.
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This is the force making the system go
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so I'd put it in my three
kilograms times nine point eight.
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And at this point,
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you might be like, "Well,
okay, that gravity made it go.
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"Should I include this gravity, too?"
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But no, that gravity is
perpendicular to the motion for one
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so this gravity isn't making the system,
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that's just causing this
mass to sit on the table
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and for two, it's cancelled
by that normal force.
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So those cancel anyway,
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even though they're external forces.
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This is it, this is the only
one that drives the system.
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So I put that in here and
I divide by my total mass
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'cause that tells me how
much my system resists
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through inertia,
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changes in velocity,
and this is what I get.
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I get the same thing I got before,
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I get back my three point six eight
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meters per second squared,
and I get in one line.
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I mean, this trick is
amazing and it works,
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and it works in every example
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where two masses or more masses
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are forced to move with
the same acceleration.
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So this is great. This'll
save you a ton of time.
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This is supposed to be a three here.
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And to show you how useful it is,
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let say there was friction,
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let's say there was a
coefficient of friction
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of zero point three.
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Well, now I'd have a frictional force
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so there'd be an external
frictional force here.
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It'd be applied this five kilogram mass.
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I'd have to subtract it up here.
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So if I get rid of this---
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So it's not gonna be three
point six eight anymore.
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I'm gonna have a force of
friction that I have to subtract.
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So minus mu K so the force of friction---
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I'll just put force of friction.
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And so to solve for the force of friction,
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the force of friction
is gonna be equal to---
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Well, I know three times
nine point eight is---
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Let me just write this in here,
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29.4 Newtons minus the force
of friction it's given by.
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So there's a formula
for force of friction.
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The force of friction is always mu K FN.
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So the force of friction
on this five kilogram mass
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is gonna be mu K which is point three.
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So it's gonna be zero point
three times the normal force,
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not the normal force on our entire system.
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I don't include this three kilogram mass.
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It's only the normal force
on this five kilogram mass
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that's contributing to this
force of friction here.
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So even though we're treating
this system as a whole,
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we still have to find individual forces
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on this individual boxes correctly.
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So it won't be the entire
mass that goes here.
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The normal force on the five kilogram mass
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is just gonna be five kilograms
times nine point eight
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meters per second squared.
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I divide by my total mass down here
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because the entire mass is
resisting motion through inertia.
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And if I solve this from my
acceleration of the system,
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I get one point eight four
meters per seconds squared.
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So this is less, less than
our three point six eight
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and that makes sense.
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Now, there's a resistive force,
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a resistive external force,
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tryna prevent the system from moving.
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But you have to be careful.
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What I'm really finding here,
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I'm really finding the
magnitude of the acceleration.
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This is just giving me the magnitude.
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If I'm playing this game
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where positive forces
are ones that make it go
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and negative forces are
ones that resist motion,
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external forces that is,
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I'm just getting the
magnitude of the acceleration.
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Individual boxes will have that magnitude
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of the acceleration
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but they may have positive
or negative accelerations.
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In other words,
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this five kilogram mass
accelerating to the right,
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gonna have a positive acceleration.
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In other words, the acceleration
of the five kilogram mass
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will be positive one point eight four
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and the acceleration of
the three kilogram mass
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since it's accelerating downward
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will be negative one point eight four
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meters per seconds squared.