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In this lesson we're going to learn about significant figures.
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When students first learn about significant figures in chemistry or physics class
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you always think it's like the most useless thing in the world.
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and just a big waste of time.
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Most people hate significant figures when they first learn them.
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The problem is, the one group of people who don't hate significant figures
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are teachers, which love them.
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And teachers also, it seems, love to take points off of tests
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when people don't get their significant figures quite right.
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So no matter what stage you are, in learning chemistry or physics,
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even if you're in the middle of the year,
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it's a great help to refresh significant figures.
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Because there are plenty of points that can be earned
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on homework assignments, quizzes and lab reports
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by brushing up on this very important topic.
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The other thing is - significant figures
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just aren't that hard when you really spend a little bit of time practicing them.
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One of the most difficult things about significant figures, I think,
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is that students don't really understand what they're for -
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what the purpose of them is.
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Here, let me show you. Here's an example.
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Let's imagine that we want to do a pretty simple calculation.
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We want to take 62 - divided by 41.
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We plug this into our calculator and we get a really ugly answer.
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The answer that we get, what the calculator is going to spit out,
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is going to be 1.512195122.
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How's that for an ugly answer?
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Now, here's the thing. You obviously don't want to put this whole thing down on your sheet,
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so you're going to ask your teacher - how many numbers do we need to round it to?
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Well, that's the thing about significant figures.
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If you understand significant figures, you don't need to ask your teacher that question.
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Because the answer to that question - how many numbers do we round it to -
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is already answered by the numbers you divided in the first place.
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Let me show you what I mean.
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I'll give you a demonstration first, and then I'll explain the details.
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62 has two significant figures in it.
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A 6 and a 2. Two significant figures.
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41 has a 4 and a 1 - also two significant figures.
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That means that I'm going to round the answer that I got to two numbers - simple as that.
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So that 1 is going to stay and the 5 is going to stay.
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But remember, I'm going to be rounding.
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So I'm going to have to look at the number next to the 5 to determine whether I keep the 5 the same,
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or if it's a big number, if I'm going to round up to 6.
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In this case it's a 1 so I don't round up.
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I keep it as 1.5.
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And that's my final answer.
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The question of how many numbers I need to round it to -
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is already answered by the number of significant figures in the numbers that I divided together.
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Now, the question you may ask is - how did I know that there were two significant figures in the 62 and the 41?
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The answer is pretty simple.
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Any number that isn't zero is always a significant figure.
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We'll talk about zero in the next lesson because it can get a little bit tricky.
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Let's take a look at another example.
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Let's do 782 divided by 231.
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Put that into the calculator again. We get a really ugly answer out.
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3.385 blah blah blah.
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I don't want to put that whole thing on my sheet either.
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So I look at the numbers that I divided together.
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How many significant figures in 782? Well, none of them are zero, so - 3 significant figures here.
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They're all significant.
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231? No number zero - 3 significant figures here.
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What does that mean? It means that I'm going to round my answer to 3 significant figures.
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This is going to stay, this is going to stay, and this is going to stay.
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As before, I'm rounding, so I look at the number to the right of this 8.
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It's a 5, which means that I'm going to have to round up.
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That 8 is going to become a 9.
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And my final answer is going to be 3.39.
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Again - it's 3.39 because that 5 there makes me round the 8 up.
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Let's go to one more example.
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1219 divided by 3462. Another pretty ugly number.
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Dot 352109.
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How many numbers do I round it to?
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I'm sure you've already gotten the hang of it.
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Four significant figures here, four significant figures here -
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That means I round my answer to - you guessed it - four significant figures.
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This stays, this stays, this stays, and this stays.
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And I look at the number just to the right of the 1. It's a zero so I certainly don't round it up.
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My final answer is going to be .3521.
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There you go. Rounded to four significant figures.
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Now, we can do this exact same thing with multiplication.
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All we have to do is round, and then we add a couple zeros if we need to.
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Let me show you what I mean.
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When I take 56 and multiply it by 28, the answer that I get is 1568.
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But as with division, I look at the significant figures in the two numbers I multiplied together -
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two here and two here -
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which means that I'm going to round my final answer to two numbers.
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This one stays and this one stays,
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and I look to the right of it to decide whether I round up or down.
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It's a 6, so I round up.
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My final answer becomes 1,6 - because these two numbers stay -
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and I just fill everything else in with zeros. So I get 1,600.
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If I multiply these guys together, 4833 times 1741, I get a really big number -
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8 million, 414 thousand, 253.
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Again - how can I round this using significant figures?
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4 significant figures here and 4 significant figures here, so -
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You guessed it - I round my answer to 4 digits.
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I look here to find out whether I round up or down.
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It's a 2 so it stays the same - 8,414 - and I fill the rest of the number in with zeros.
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I don't need them.
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Round it to four digits.
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Now, if you're smart, you've already realized that I'm doing something pretty simple.
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All the numbers that I have been multiplying together or dividing have the same number of significant figures.
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So maybe you're asking yourself - OK, this seems easy enough,
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but what would I do if I had to multiply together or divide two numbers that didn't have the same number of significant figures?
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What if, like for example, one had 5 and one had 2 -
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How would I round then? Let's take a look.