Proof: A(log B) = log (B^A), log A - log B = log (A/B)

Title:: Proof: A(log B) = log (B^A), log A - log B = log (A/B)
Description:: Proofs of the logarithm properties: A(log B) = log (B^A) and log A - log B = log (A/B)

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Video Language:: English
Duration:: 07:57

	Gina_Andrei edited Romanian subtitles for Proof: A(log B) = log (B^A), log A - log B = log (A/B)
	nurgaleevraule edited Russian subtitles for Proof: A(log B) = log (B^A), log A - log B = log (A/B)
	nurgaleevraule deleted url http://www.youtube.com/watch?v=yEAxG_D1HDw
	nurgaleevraule edited Russian subtitles for Proof: A(log B) = log (B^A), log A - log B = log (A/B)
	nurgaleevraule edited Russian subtitles for Proof: A(log B) = log (B^A), log A - log B = log (A/B)
	nurgaleevraule edited Russian subtitles for Proof: A(log B) = log (B^A), log A - log B = log (A/B)
	nurgaleevraule changed primary url from http://www.youtube.com/watch?v=yEAxG_D1HDw to http://www.youtube.com/watch?v=3iJgHCV8nmY
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