- 
- 
Let's see if we can simplify 5
 times the square root of 117.
 
- 
So 117 doesn't jump out at me as
 some type of a perfect square.
 
- 
So let's actually take
 its prime factorization
 
- 
and see if any of those prime
 factors show up more than once.
 
- 
So clearly it's an odd number. 
- 
It's clearly not divisible by 2. 
- 
To test whether
 it's divisible by 3,
 
- 
we can add up all of the digits. 
- 
And we explain why this works in
 another place on Khan Academy.
 
- 
But if you add up all
 the digits, you get a 9.
 
- 
And 9 is divisible by 3, so 117
 is going to be divisible by 3.
 
- 
Now, let's do a
 little aside here
 
- 
to figure out what 117
 divided by 3 actually is.
 
- 
So 3 doesn't go into 1. 
- 
It does go into 11, three times. 
- 
3 times 3 is 9. 
- 
Subtract, you got
 a remainder of 2.
 
- 
Bring down a 7. 
- 
3 goes into 27 nine times. 
- 
9 times 3 is 27. 
- 
Subtract, and you're done. 
- 
It goes in perfectly. 
- 
So we can factor
 117 as 3 times 39.
 
- 
Now 39, we can factor as--
 that jumps out more at us
 
- 
that that's divisible by 3. 
- 
That's equivalent to 3 times 13. 
- 
And then all of these
 are now prime numbers.
 
- 
So we could say that this
 thing is the same as 5 times
 
- 
the square root of
 3 times 3 times 13.
 
- 
- 
And this is going to be the
 same thing as-- and we know this
 
- 
from our exponent
 properties-- 5 times
 
- 
the square root of 3 times 3
 times the square root of 13.
 
- 
Now, what's the square
 root of 3 times 3?
 
- 
Well, that's the
 square root of 9.
 
- 
That's the square
 root of 3 squared.
 
- 
Any of those-- well, that's
 just going to give you 3.
 
- 
So this is just going
 to simplify to 3.
 
- 
So this whole thing is 5 times
 3 times the square root of 13.
 
- 
So this part right over
 here would give us 15 times
 
- 
the square root of 13. 
- 
Let's do one more example here. 
- 
So let's try to simplify 3
 times the square root of 26.
 
- 
I'm actually going
 to put 26 in yellow,
 
- 
like I did in the
 previous problem.
 
- 
Well, 26 is clearly
 an even number,
 
- 
so it's going to
 be divisible by 2.
 
- 
We can rewrite it as 2 times 13. 
- 
And then we're done. 
- 
13 is a prime number. 
- 
We can't factor this any more. 
- 
And so 26 doesn't have
 any perfect squares in it.
 
- 
It's not like we
 can factor it out
 
- 
as a factor of
 some other numbers
 
- 
and some perfect squares
 like we did here.
 
- 
117 is 13 times 9. 
- 
It's the product of a
 perfect square and 13.
 
- 
26 isn't, so we've simplified
 this about as much as we can.
 
- 
We would just leave this as 3
 times the square root of 26.
 
-