< Return to Video

Simplifying square roots

  • 0:00 - 0:09
    Let's see if we can simplify 5
    times the square root of 117.
  • 0:09 - 0:13
    So 117 doesn't jump out at me as
    some type of a perfect square.
  • 0:13 - 0:15
    So let's actually take
    its prime factorization
  • 0:15 - 0:20
    and see if any of those prime
    factors show up more than once.
  • 0:20 - 0:22
    So clearly it's an odd number.
  • 0:22 - 0:24
    It's clearly not divisible by 2.
  • 0:24 - 0:26
    To test whether
    it's divisible by 3,
  • 0:26 - 0:27
    we can add up all of the digits.
  • 0:27 - 0:30
    And we explain why this works in
    another place on Khan Academy.
  • 0:30 - 0:32
    But if you add up all
    the digits, you get a 9.
  • 0:32 - 0:36
    And 9 is divisible by 3, so 117
    is going to be divisible by 3.
  • 0:36 - 0:38
    Now, let's do a
    little aside here
  • 0:38 - 0:41
    to figure out what 117
    divided by 3 actually is.
  • 0:41 - 0:44
    So 3 doesn't go into 1.
  • 0:44 - 0:46
    It does go into 11, three times.
  • 0:46 - 0:48
    3 times 3 is 9.
  • 0:48 - 0:50
    Subtract, you got
    a remainder of 2.
  • 0:50 - 0:53
    Bring down a 7.
  • 0:53 - 0:56
    3 goes into 27 nine times.
  • 0:56 - 0:58
    9 times 3 is 27.
  • 0:58 - 0:59
    Subtract, and you're done.
  • 0:59 - 1:02
    It goes in perfectly.
  • 1:02 - 1:08
    So we can factor
    117 as 3 times 39.
  • 1:08 - 1:11
    Now 39, we can factor as--
    that jumps out more at us
  • 1:11 - 1:13
    that that's divisible by 3.
  • 1:13 - 1:16
    That's equivalent to 3 times 13.
  • 1:16 - 1:18
    And then all of these
    are now prime numbers.
  • 1:18 - 1:24
    So we could say that this
    thing is the same as 5 times
  • 1:24 - 1:35
    the square root of
    3 times 3 times 13.
  • 1:37 - 1:40
    And this is going to be the
    same thing as-- and we know this
  • 1:40 - 1:43
    from our exponent
    properties-- 5 times
  • 1:43 - 1:55
    the square root of 3 times 3
    times the square root of 13.
  • 1:55 - 1:57
    Now, what's the square
    root of 3 times 3?
  • 1:57 - 1:58
    Well, that's the
    square root of 9.
  • 1:58 - 2:00
    That's the square
    root of 3 squared.
  • 2:00 - 2:02
    Any of those-- well, that's
    just going to give you 3.
  • 2:02 - 2:05
    So this is just going
    to simplify to 3.
  • 2:05 - 2:10
    So this whole thing is 5 times
    3 times the square root of 13.
  • 2:10 - 2:15
    So this part right over
    here would give us 15 times
  • 2:15 - 2:20
    the square root of 13.
  • 2:20 - 2:22
    Let's do one more example here.
  • 2:22 - 2:30
    So let's try to simplify 3
    times the square root of 26.
  • 2:30 - 2:32
    I'm actually going
    to put 26 in yellow,
  • 2:32 - 2:35
    like I did in the
    previous problem.
  • 2:35 - 2:37
    Well, 26 is clearly
    an even number,
  • 2:37 - 2:39
    so it's going to
    be divisible by 2.
  • 2:39 - 2:42
    We can rewrite it as 2 times 13.
  • 2:42 - 2:43
    And then we're done.
  • 2:43 - 2:44
    13 is a prime number.
  • 2:44 - 2:46
    We can't factor this any more.
  • 2:46 - 2:48
    And so 26 doesn't have
    any perfect squares in it.
  • 2:48 - 2:50
    It's not like we
    can factor it out
  • 2:50 - 2:51
    as a factor of
    some other numbers
  • 2:51 - 2:53
    and some perfect squares
    like we did here.
  • 2:53 - 2:55
    117 is 13 times 9.
  • 2:55 - 2:59
    It's the product of a
    perfect square and 13.
  • 2:59 - 3:02
    26 isn't, so we've simplified
    this about as much as we can.
  • 3:02 - 3:08
    We would just leave this as 3
    times the square root of 26.
Title:
Simplifying square roots
Description:

more » « less
Video Language:
English
Team:
Khan Academy
Duration:
03:09

English subtitles

Revisions Compare revisions