Partial products for multiplying 2 by 1 digits | 3rd grade math (TX TEKS) | Khan Academy

- [Instructor] We're told
to use partial products

to multiply 67 times nine.

And so they wrote 67 times nine here

and they broke out some of the steps.

And so let's just think
about what's happening.

It looks like Step 1,

we're doing a partial product
of nine times something.

And then Step 2,

we have another partial
product of nine times 60.

So this right over
here, the nine times 60,

which is equal to 540,

that's when essentially you took

the nine and you multiplied it

times the six tens right over there.

So that's nine times the 60.

So Step 1, the way you
could think about it

is this is going to be
nine times the one's place.

So this is going to be nine times seven.

And what is nine times seven?

That is going to be 63.

And so if you take nine times seven

and you add that to nine times 60,

well, then, you're going to
get what nine times 67 is.

And so let's add all of this together.

Three plus zero is three.

Six plus four is 10.

We can write a zero there
and regroup that one.

And then 100 plus 500 is 600.

So that is 603.

Or you might recognize, 540 plus 63,

540 plus 60 is 600,

plus another three is 603, and we're done.