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Distributive property with variables exercise

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    We're asked to apply the
    distributive property.
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    And we have 1/2 times the expression
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    2a-6b+8.
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    So, to figure this out,
    I've actually already
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    copy and pasted this
    problem onto my scratch pad.
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    I have it right over here.
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    1/2(2a-6b+8).
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    So, lemme just rewrite it.
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    So, I'm gonna take, and
    lemme color code it, too,
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    just for fun, so it's going to be 1/2
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    times, give myself some space,
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    1/2(2a-6b),
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    so, 2a-6b,
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    minus six, lemme write it this way
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    - 6b, and then we have plus eight.
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    Plus, and I will do eight in this color.
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    +8.
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    And so, i just need to distribute the 1/2.
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    If I multiplying 1/2 times
    this entire expression,
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    that means I multiply 1/2
    times each of these terms.
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    So, I'm gonna multiply 1/2 times this,
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    1/2 times this, and 1/2 times that.
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    So, 1/2 times 2a, so this is going to be
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    1/2 times 2a, times,
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    lemme do it in that same color
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    so you see where the 2a came from.
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    1/2(2a) minus,
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    minus 1/2(6b).
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    Minus 1/2(6b).
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    Times 6b+1/2(8).
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    1/2(8).
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    And so, what's this going to be?
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    Well, let's see, I have 1/2(2a).
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    1/2(2) is just one, so you're just
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    going to be left with A.
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    And then you have minus 1/2(6b).
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    Well, we could just think about what
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    1/2(6) is going to be.
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    1/2(6) is going to be three, and then you
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    still are multiplying times B.
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    So, it's gonna be 3b.
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    And then we have plus 1/2(8).
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    Half of eight is four.
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    Or as you can say, eight
    halves is equal to four wholes.
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    Alright, so this is going to be four.
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    So, it's a-3b+4,
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    a-3b+4.
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    So, let's type that in.
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    It's going to be
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    a-3b+4.
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    And notice, it's just literally half
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    of each of these terms.
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    Half of 2a is A, half of 6b is 3b,
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    so we have minus 6b, so
    it's gonna be minus 3b,
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    and then plus eight, instead of that,
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    half of that plus four.
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    So, let's check our answer.
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    And we got it right.
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    Let's do another one of these.
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    So, let's say,
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    so, they say apply the
    distributive property
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    to factor out the greatest common factor.
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    And here, we have 60m-40,
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    so lemme get my scratch pad out again.
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    So, I'm running out of space that way.
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    So, we have, write it like this.
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    We have 60,
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    60m-40.
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    Minus 40.
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    So, what is the greatest common factor
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    of 60m and 40?
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    Well, 10 might jump out at us.
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    We might say, okay, look, you know?
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    60 is 10, so we could say
    this is the same thing
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    as 10 times six and actually, and then,
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    of course, you have the M there,
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    so you could do this 10 times 6m.
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    And then you could view,
    you could view this as
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    10 times four.
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    But we, 10 still isn't the
    greatest common factor.
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    You'll say, well, how do you know that?
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    Well, because four and six still share
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    a factor in common.
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    They still share two.
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    So, if you're actually factoring out
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    the greatest common factor, what's left
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    should not share a factor with each other.
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    So, let me think even harder about
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    what a greatest common
    factor of 60 and 40 is.
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    Well, two times 10 is 20.
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    So, you could actually factor out a 20.
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    So, you have 20 and 30m.
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    Sorry, 20 and 3m.
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    And 40 could be factored out into 20 and,
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    20 and two.
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    And now 3m and two, 3m and
    two share no common factors.
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    So, you know that you have fully factored
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    these two things out.
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    Now, if you think this is something
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    kind of a strange art that I just did,
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    one way to think about
    greatest common factors,
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    you say, okay, 60, you could literally do
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    a prime factorization.
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    You could say 60 is two times
    30, which is two times 15,
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    which is three times five.
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    So, that's 60's prime factorization.
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    Two times two times three times five.
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    And then 40's prime factorization
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    is two times 20, 20 is two times 10.
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    10 is two times five.
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    So, that right over here, this
    is 40's prime factorization.
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    And to get out the greatest common factor,
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    you wanna get out as many
    common prime factors.
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    So you have, here, you
    have two twos and a five.
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    Here, you have two twos and a five.
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    You can't go to three twos and a five
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    'cause there aren't three
    twos and a five over here.
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    So, we have two twos and a five here.
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    Two twos and a five here.
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    So, two times two times
    five is going to be
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    the greatest common factor.
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    So, two times two times
    five, that's four times five.
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    Four times five, that is 20.
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    That's one way of kind
    of very systematically
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    figuring out a greatest common factor.
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    But anyway, now that we know that 20
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    is the greatest common
    factor, let's factor it out.
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    So, this is going to be equal to 20 times,
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    so 60m divided by 20, you're
    just going to be left with 3m.
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    Just going to be left with 3m.
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    And then minus, minus 40 divided by 20,
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    you're just left with the two.
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    Minus two.
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    Minus two, so let's type that in.
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    So, this is going to be 20 times,
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    20(3m-2).
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    And once again, we feel good that we,
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    literally, we did take out
    the greatest common factor
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    because 3m and two,
    especially three and two
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    are now relatively prime.
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    Relatively prime just
    means they don't share
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    any factors in common other than one.
Title:
Distributive property with variables exercise
Description:

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Video Language:
English
Team:
Khan Academy
Duration:
06:29

English subtitles

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