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Vector representation of a surface integral | Multivariable Calculus | Khan Academy

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    In the last video,
    we figured out
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    how to construct a unit
    normal vector to a surface.
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    And so now we can use that
    back in our original surface
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    integral to try to
    simplify a little bit,
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    or at least give us a clue how
    we can calculate these things.
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    And also, think
    about different ways
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    to represent this type
    of a surface integral.
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    So if we just substitute what
    we came up as our normal vector,
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    our unit normal
    vector right here,
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    we will get-- so
    once again, it's
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    the surface integral of F dot.
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    And F dot all of this
    business right over here.
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    And I'm going to
    write it all in white,
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    just so it doesn't
    take me too much time.
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    So the partial of
    r with respect to u
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    crossed with the partial
    of r with respect
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    to v over the magnitude
    of the same thing, partial
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    of r with respect to u
    crossed with the partial of r
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    with respect to v.
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    And now, we've
    played with ds a lot.
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    We know that the other
    way to write ds--
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    and I gave the
    intuition, hopefully,
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    for that several videos
    ago when we first
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    explored what a surface
    integral was all about.
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    We know that ds is--
    it can be represented
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    as the magnitude of the
    partial of r with respect
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    to u crossed with the partial
    of r with respect to v du dv.
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    And Obviously, the du dv, it
    could be written as dv du.
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    You could write it as da,
    a little chunk of area
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    and the uv plane or
    in the uv domain.
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    And actually, since now this
    integral's in terms of uv,
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    we're no longer taking
    a surface integral.
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    We're now taking a double
    integral over the uv domain.
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    So you could say kind
    of a region in uv.
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    So I'll say R to say that's
    it's a region in the uv plane
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    that we're now thinking about.
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    But there's probably a
    huge-- or there should be,
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    or I'm guessing there's a
    huge simplification that's
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    popping out at you right now.
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    We're dividing by the
    magnitude of the cross product
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    of these two vectors
    and then we're
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    multiplying by the magnitude of
    the cross product of these two
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    vectors.
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    Those are just
    scalar quantities.
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    You divide by something
    and multiply by something.
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    Well, that's just the same
    thing as multiplying or dividing
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    by 1.
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    So these two
    characters cancel out,
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    and our integral simplifies
    to the double integral
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    over that region, the
    corresponding region in the uv
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    plane, of F-- of
    our vector field F
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    dotted with this cross product.
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    This is going to give us
    a vector right over here.
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    That's going to
    give us a vector.
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    It gives us actually
    a normal vector.
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    And then when you
    divide by its magnitude,
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    it gives you a
    unit normal vector.
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    So this, you're going to
    take the dot product of F
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    with r, the partial
    of r with respect
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    to u crossed with the partial
    of r with respect to v du dv.
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    Let me scroll over to the
    right a little bit, du dv.
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    And we'll see in the
    few videos from now
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    that this is essentially how we
    go about actually calculating
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    these things.
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    If you have a
    parameterization, you
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    can then get everything in
    terms of a double integral,
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    in terms of uv this way.
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    Now, the last thing I want
    to do is explore another way
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    that you'll see a surface
    integral like this written.
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    It all comes from,
    really, writing this part
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    in a different way.
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    But it hopefully gives you
    a little bit more intuition
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    of what this thing
    is even saying.
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    So I'm just going to rewrite.
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    I'm going to rewrite this
    chunk right over here.
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    I'm just going to
    rewrite that chunk.
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    And I'm going to use slightly
    different notation because it
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    will hopefully help make
    a little bit more sense.
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    So the partial of r
    with respect to u I
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    can write as the partial
    of r with respect to u.
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    And we're taking
    the cross product.
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    Let me make my u's a little bit
    more u-like so we confuse them
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    with v's.
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    And we're taking the
    cross product of that
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    with the partial
    of r with respect
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    to v. So very small
    changes in our vector--
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    in our parameterization
    right here,
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    our position vector given
    a small change in v. Very
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    small changes in the vector
    given a small change in u.
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    And then we're multiplying
    that times du dv.
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    We're multiplying
    that times du dv.
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    Now, du and dv are
    just scalar quantities.
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    They're infinitesimally small.
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    But for the sake
    of this argument,
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    you can just view--
    they're not vectors,
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    they're just scalar quantities.
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    And so you can
    essentially include them--
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    if you have the cross product.
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    If you have a cross b times some
    scalar value-- I don't know, x,
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    you could rewrite this
    as x times a cross b,
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    or you could write
    this as a cross x times
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    b, because x is
    just a scalar value.
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    It's just a number.
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    So we could do the
    same thing over here.
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    We can rewrite all
    of this business as--
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    and I'm going to group the du
    where we have the partial--
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    or with respect to u
    in the denominator.
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    And I'll do the same
    thing with the v's.
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    And so you will get the
    partial of r with respect
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    to u times du,
    times that scalar.
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    So that'll give us a vector.
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    And we're going to cross that.
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    We're going to cross that with
    the partial of r with respect
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    to v dv.
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    Now, these might
    look notationally
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    like two different
    things, but that just
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    comes from the
    necessity of when we
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    take partial derivatives to say,
    oh, no, this vector function
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    is defined-- it's a function
    of multiple variables
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    and this is taking a
    derivative with respect
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    to only one of them.
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    So this is, how
    much does our vector
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    change when you have a
    very small change in u?
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    But this is also an
    infinitesimally small change
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    in u over here, we're just using
    slightly different notation.
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    So for the sake of--
    and this is a little bit
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    loosey-goosey mathematics,
    but it will hopefully
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    give you the intuition
    for why this thing could
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    be written in a different way.
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    These are essentially
    the same quantity.
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    So if you divide by something
    and multiply by something,
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    you can cancel them out.
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    If you divide by something
    and multiply by something,
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    you can cancel them out.
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    And all you're left
    with then-- all
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    you're left with is
    the differential of r.
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    And since we lost
    the information
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    that it's in the
    u-direction, I'll
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    write here, the differential
    of r in the u-direction.
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    I don't want to get
    the notation confused.
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    This is just the differential.
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    This is just how much r changed.
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    This is not the partial
    derivative of r with respect
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    to u.
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    This right over here
    is, how much does r
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    change given per unit change,
    per small change in u?
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    This just says a differential
    in the direction of-- I
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    guess as u changes, this is
    how much that infinitely small
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    change that just r changes.
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    This isn't change in r with
    respect to change in u.
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    And we're going to cross that.
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    Now, we're going to cross
    that with the partial of r,
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    the partial of r
    in the v-direction.
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    Now, this right over here,
    let's just conceptualize this.
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    And this goes back to
    our original visions
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    of what a surface
    integral was all about.
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    If we're on a surface--
    and I'll draw surface.
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    Let me draw another surface.
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    I won't use the one that
    I had already drawn on.
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    If we draw a surface, and for
    a very small change in u--
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    and we're not going to
    think about the rate.
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    We're just thinking about
    kind of the change in r.
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    You're going in that direction.
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    So if that thing
    looks like this,
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    this is actually kind of a
    distance moved on the surface.
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    Because remember, this
    isn't the derivative.
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    This is the differential.
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    So it's just a small
    change along the surface,
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    that's that over there.
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    And that this is a small
    change when you change v. So
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    it's also a change
    along the surface.
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    When you take the cross
    product of these two things,
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    you get a vector
    that is orthogonal.
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    You get a vector that is
    normal to the surface.
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    So it is normal to the
    surface and its magnitude--
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    and we saw this when we first
    learned about cross products.
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    Its magnitude is
    equal to the area that
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    is defined by these two vectors.
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    So its magnitude
    is equal to area.
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    So in a lot of
    ways, you can really
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    think of it-- you
    really could think
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    of it as a unit normal
    vector times ds.
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    And so the way that we would,
    I guess notationally do this,
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    is we can call this--
    because this is kind of a ds,
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    but it's a vector
    version of the ds.
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    Over here, this is just
    an area right over here.
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    This is just a scalar value.
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    But now, we have a vector
    that points normally
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    from the surface,
    but its magnitude
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    is the same thing as
    that ds that we were just
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    talking about.
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    So we can call this thing right
    over here, we can call this ds.
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    And the key difference here
    is this is a vector now.
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    So we'll call it ds with
    a little vector over it
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    to know that this thing.
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    This isn't the scalar ds that
    is just concerned with the area.
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    But when you view
    things this way,
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    we just saw that this entire
    thing simplifies to ds.
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    Then our whole surface
    integral can be rewritten.
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    Instead of writing
    it like this, we
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    can write it as the
    integral or the surface
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    integral-- those integral
    signs were too fancy.
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    The surface integral of F dot.
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    And instead of saying a
    normal vector times the scalar
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    quantity, that little chunk
    of area on the surface,
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    we can now just call that
    the vector differential ds.
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    And I want to make it clear,
    these are two different things.
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    This is a vector.
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    This is essentially
    what we're calling it.
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    This right over here is a
    scalar times a normal vector.
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    So these are three
    different ways
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    of really representing
    the same thing.
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    And in different contexts,
    you will see different things,
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    depending on what the author of
    whoever's trying to communicate
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    is trying to communicate.
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    This right over here is the one
    that we'll use most frequently
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    as we actually try to calculate
    these surface integrals.
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Title:
Vector representation of a surface integral | Multivariable Calculus | Khan Academy
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Video Language:
English
Team:
Khan Academy
Duration:
09:35

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