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Properties of Logarithms

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    INSTRUCTOR: In this video, we're briefly going to go over
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    some properties of logs that you need to be familiar with.
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    The first one is the power rule.
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    Let's say if you have log A raised to the N.
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    You can move the exponent in front.
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    This is equal to N log A.
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    The second is the product rule.
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    Log A times log B is equal to log A plus log B.
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    Then you have the quotient rule.
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    Log A divided by log B is log A minus log B.
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    We can use this in order to evaluate logs.
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    For instance, let's say if we want to simplify log base 5 that's 5 raised to 7.
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    What we can do is move the 7 to the front.
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    This is equal to 7 log base 5 of 5.
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    A log base 5 of 5 because they're the same,
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    it's equal to 1 and 7 times 1 is 7.
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    Let's try another example like that.
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    Log base 2 of 8 raised to fifth power.
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    Let's move the 5 to the front.
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    This is equal to 5 times log base 2 of 8.
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    Now, how many 2s do we need to multiply to get to 8?
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    We need to multiply 3 2s, 2 to the third is 8,
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    so log base 2 of 8 is 3,
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    and 5 times 3 is 15.
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    Now let's work on this example.
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    Log base 2 of 16 times 8.
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    We can use the product rule to separate the 16 and the 8.
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    If you recall, log of A times B equals log A plus log B.
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    Therefore, log base 2 of 16 times 8 is going to be log base 2
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    of 16 plus log base 2 of 8.
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    Now, log base 2 of 16,
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    that's 4 because 2 to the fourth power is 16.
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    Log base 2 of 8 is 3.
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    The final answer is 4 plus 3 which is 7.
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    Try this one. Log base 3 of 27 times 81.
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    First, let's separate it into two logs.
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    This is log base 3 of 27 plus log base 3 of 81.
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    3 to the third power is 27, so log base 3 of 27 is 3.
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    Log base 3 of 81 is 4 because 3 to the fourth power is 81,
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    and this adds to 7. What about division?
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    What is log base 4 of 256 minus 64?
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    Using the quotient rule,
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    log A divided by B is equal to log A minus log B.
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    Therefore, this is going to be
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    log base 4 of 256 minus log base 4 of 64.
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    4 to the fourth power is 256,
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    and 4 to the third power is 64,
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    and 4 minus 3 is 1. That's going to be the answer.
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    Try this one, log base 2 of 128 over 8.
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    This is equal to log base 2 of 128 minus log base 2 of 8.
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    Now, 2 to the seventh power is 128 and 2 to the third is 8.
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    Seven minus 3 is 4 and that's going to be the answer.
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    Here's the last example. Log base 2 of 128 times 64 divided by 8 times 16 raised to the fifth power.
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    The first thing we should do is move the
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    five and it's going to be distributed to everything.
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    Now, every number that's on top will have a positive sign.
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    The numbers on the bottom will have a negative sign.
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    It's going to be log base 2 of 128 plus log base 2 of 64 since they're multiplied to each other,
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    minus log base 2 of 8,
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    since it's divided by,
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    and also minus log base 2 of 16.
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    Log base 2 of 128, we know it's 7,
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    2 to the sixth power is 64,
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    2 to the third is 8, 2 to the fourth is 16.
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    Negative 3 and negative 4 adds up to negative 7,
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    which cancels with the positive 7.
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    The final answer is 5 times 6 which is 30.
Title:
Properties of Logarithms
Description:

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Video Language:
English
Team:
BYU Continuing Education
Project:
PHSCS-105-300
Duration:
05:40

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